A is the poin 3,5 and b is the point 0,k if the distance of ab is 5 units find the possible value of k

K is either 9 or 1

Step-by-step explanation:

Sqrt((0 - 3)² + (k - 5)²) = 5

Square both sides

(0 - 3)² + (k - 5)² = 5²

(0 - 3)² + (k - 5)² = 25

-3² + (k - 5)² = 25

9 + (k-5)(k-5) = 25

9 + k² - 5k - 5k + 25 - 25 = 0

k² - 10k +9 = 0

k² - 9k - k + 9 = 0

k(k - 9) - 1(k - 9) = 0

k - 1 = 0 ; k = 1

k - 9 = 9; k = 1

K = 9 or k = 1

K is either 9 or 1

the answer is a if my teacher taught me correct