The width of a rectangle is 6n - 2.5 feet and the length is 2.5 + 8 feet. Find the perimeter of the rectangle.

I was thinking the measurement for ;length should be 2.5n + 8 feet since width is 6n -2.5 feet , but you gave 2.5+ 8 feet, so i will solve it in both ways

 Perimeter =  5 + 12n + 11 feet ; Perimeter =  17n+ 11 feet

Step-by-step explanation:

Using Length = 2.5+ 8 feet,

Perimeter of  a rectangle is calculated as 2( l+ b)

Given that width=6n - 2.5 feet

length =2.5 + 8 feet

Perimeter =2( l+ b)= 2L + 2B

Perimeter= 2(2.5 + 8feet ) + 2( 6n - 2.5 feet)

Perimeter = 5 + 16feet + 12n - 5feet

Perimeter =  5 + 12n + 11 feet

Using Length = 2.5n+ 8 feet,

Perimeter of  a rectangle is calculated as 2( l+ b)

Given that width=6n - 2.5 feet

length =2.5n+ 8 feet

Perimeter =2( l+ b)= 2L + 2B

Perimeter= 2(2.5n + 8feet ) + 2( 6n - 2.5 feet)

Perimeter = 5n + 16feet + 12n - 5feet

Perimeter =  5n + 12n + 11 feet

Perimeter =  17n+ 11 feet

0.02

step-by-step explanation:

time of 9 192 631 770 periods of the radiation corresponding to the transition between the 2 hyperfine levels of the ground state of the caesium 133 atom at 0 k (but other seconds are sometimes used in astronomy)

12

step-by-step explanation: