What values of x is log (2x-5) valid

To solve this you must first know how Log works.

When we say log1000 of base 10

Or

log1000=3

What we actually say is for the power 3(value on RHS) of 10(the base of log) we get 1000(the value on which log is performed).

So log2x=−5 (i am assuming base 10 since it is simple algebra) means that

2x=10−5

x=10−5/2

Do this simple calculation and you have it. If anything is unclear/incorrect feel free to comment.

The question is not written properly, so I will give the answer(s) I think would be suitable.

If you were trying to solve this

log2x=−5

⟹x=2−5

⟹x=132

But if you were trying to solve this

log2x=−5

⟹log102x=−5

⟹2x=10−5

⟹x=12×105=1200000

Step-by-step explanation:

Hope it is helpful...

when studying polynomials, you often hear the terms zeros, roots, factors and x x the multiplicity of a zero is important because it tells us how the graph of the let's look at the graph of a function that has the same zeros

step-by-step explanation: