Suppose we select without looking one marbles de containing 5 red marbles and 7 green marbles What is the probability of selecting each of the following a) A red marble c) A purple marble b) A green marble d) Ared or a green marble a) What is the probably 3​

a) 5/12 probability of selecting a red marble.

b) 7/12 probability of selecting a green marble.

c) 0% probability of selecting a purple marble.

d) All marbles are either red or green, so 100% probability of selecting a red or a green marble

Step-by-step explanation:

A probability is given by the number of desired outcomes divided by the number of total outcomes.

a) A red marble

5 red marbles out of 5 + 7 = 12 total marbles

So, 5/12 probability of selecting a red marble.

b) A green marble

7 green marbles out of 5 + 7 = 12 total marbles

So, 7/12 probability of selecting a green marble.

c) A purple marble

There are no purple marbles, so 0% probability of selecting a purple marble.

d) A red or a green marble

All marbles are either red or green, so 100% probability of selecting a red or a green marble

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v