David invests $7000 in two different accounts. The first account paid 4 %, the second account paid 8 % in interest. At the end of the first year he had earned $476 in interest. How much was in each account?
$
at 4%
$
at 8 %
Pls show work

What we know:

I  = Invest (so we dont mess up on interest.)

So, I = $7,000

First Account is 4%

Second Account is 2%

End of the year David Earns $476 in interest

With percent's you can always turn them into a decimal.

The Question: How much was in each account?

Step by Step

I = amount invested at 4%

4% = 0.40

8% = 0.80

0.40 - $7,000 = 6999.6

0.80 - 6999.6 = 6998.8

6998.8 - 476

Amount in both accounts in total is 6522.80.

HOPE THIS HELPS! =3

HAVE A FANTASTIC DAY!

the answer

b. they are parallel and will never intersect.

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.