A rental car company charges $38.38 per day to rent a car and $0.14 for every mile driven. Camden wants to rent a car, knowing that: He plans to drive 350 miles. He has at most $270 to spend. Which inequality can be used to determine xx, the maximum number of days Camden can afford to rent for while staying within his budget?

5.75 days

Step-by-step explanation:

Given data

let the number of days be x and the number and the number of miles be y

so that the cost of the rental will be

c= 38.38x+ 0.14y1

we are told that the amount at hand is $270

hence

270=38.38x+ 0.14*(350)

solve for x

270= 38.38x+49

270-49= 38.38x

221= 38.38x

divide both sides by 38.38

x= 221/38.38

x= 5.75 days

Hence the  number of days is 5.75 days

answer: answer is b.

[m < b = 120º]

step-by-step explanation:

1. a^4+8a^3+24a^2+32a+16

2.y^8+8y^7+28y^6+56y^5+70y^4+56y^3+28y^2+8y+1

3.x^6-3x^4y^2+3x^2y^4-y^6