2х2 +6 x +4
Factorise by first taking out a common factor

2x² + 6x + 4

= 2(x² + 3x + 2)

= 2(x² + 2x + x + 2)

= 2[x(x + 2) + (x + 2)]

= 2(x + 1)(x + 2)

Step-by-step explanation:

29 mil

step-by-step explanation:

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180