Two vertical posts stand side by side. One post is 8 feet tall while the other is 17 feet tall. If a 24 foot wire is stretched between the tops of the posts, how far apart are the posts?​

22 1/4 feet

Step-by-step explanation:

you can sketch this problem to be a right triangle with a hypotenuse of 24 feet and one leg of 9 feet (17 - 8).

use Pythagorean Theorem to find the base side, which represents the distance between the posts

a² + 9² = 24²

a² + 81 = 576

a² = 576 - 81

a² = 495

a =

a = ·  =  3, which is approx 22.25

about 22.25 feet

Step-by-step explanation:

You can think of it like a triangle, which you can see at the bottom

Then, use the pythagorean theorem, .

you have a = 9 and c = 24, so

typically if you want , you would actually put questions here for us to you. but hey, that's just me. maybe someone will magically answer the questions for you without knowing what they are.

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)