The length of a recatangular garden is three feet more than four times the width. Find the perimeter and area of the garden.

The perimeter is (6+10b) and the area of the garden is (3b+4b²).

Step-by-step explanation:

Let l be the length and b be the width of the rectangle.

According to the question,

The length of a rectangular garden is three feet more than four times the width i.e.

l = 3+4b

The perimeter of a rectangle is given by :

P = 2(l+b)

Substitute all the values,

P = 2(3+4b+b)

P = 2(3+5b)

P = 6+10b

The area of a rectangle is given by :

A = lb

Substitute all the values,

A = (3+4b)b

A = 3b+4b²

So, the perimeter is (6+10b) and the area of the garden is (3b+4b²).

c.

step-by-step explanation:

she should of added 9^2 and 12^2. that is because it is a^2+b^2=c^2. c^2 is the hypotenuse and should always be bigger than the other two numbers. which is why she should of added 9 squared and 12 squared together instead of 15 squared.

answer would be 8.64 or s = 11π/4 inches

step-by-step explanation:

s = r θ  

where s = arc length  

r = radius = 3 inches  

θ = central angle in radians = ( π /180)*165  

s = 3(π/180)*165  

= 8.64 inches