Bonus: 2 points for vertex form or standard form, 5 points for both Write the equation for the quadratic function the has a vertex at (3,-5) and includes
the point (-1,11)

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Step-by-step explanation:

The vertex form of the quadratic equation is ...

  y = a(x -h)² +k . . . . . . . . . vertex (h, k); vertical scale factor 'a'

Given the vertex, we can find the scale factor by substituting the given point values:

  11 = a(-1 -3)² -5

  11 = 16a -5

  a = (11 +5)/16 = 1

So, the vertex form equation is ...

  y = (x -3)² -5 . . . . . vertex form

Expanding this gives the standard form.

  y = x² -6x +9 -5

  y = x² -6x +4 . . . . . standard form

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v