If a triangle has side lengths of 14, 48, and 50 units respectively, what type of triangle is it? An acute, obtuse, or right? Or does it have no solution?​​

I think it would be a obtuse triangle.

Step-by-step explanation:

Considering the Triangle Inequality theorem, for sides to make a triangle to two smallest sides must have a greater sum then the longest. Now that we know its a triangle we must decided what type of triangle it is. You can rule out acute because of the 14. Now, I used the 3:4:5 right triangle rule, which states that a right triangle must a a ratio of 3:4:5. Again, I think the 14 causes the triangle to be obtuse.

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3