An oval track is made by enclosing semicircles on each end of a 52 m by 104 m rectangle. Find the area enclosed by the track. Use 3.14 for a.

7,540.64 m^2

Step-by-step explanation:

The area enclosed by the track may be computed as the sum of the area of the 2 semicircles and a rectangle.

The area of a semicircle is given as

A = 1/2 Pi r^2 where r is the radius of the semicircle. Since there are 2 semicircles, the area of the two will be

= Pi r^2

r = 52/2 = 26 m

Hence the area of the two semicircles

=3.14 * 26^2

= 2,122.64 m^2

The area of the rectangle is the product of its length and width

= 104 * 52

= 5408 m^2

Total area covered by the track

= 2,122.64 + 5,408

= 7,540.64 m^2

rounding to the nearest thousandth would be 452,000

5050 i think

step-by-step explanation: