Solve for x&y, y=3x-4 & y= 2x + 1 Please show step by step how you got the answer

(5, 11 )

Step-by-step explanation:

Given the 2 equations

y = 3x - 4 → (1)

y = 2x + 1 → (2)

Substitute y = 3x - 4 into (2)

3x - 4 = 2x + 1 ( subtract 2x from both sides )

x - 4 = 1 ( add 4 to both sides )

x = 5

Substitute x = 5 into either of the 2 equationsfor corresponding value of y

Substituting into (2)

y = 2(5) + 1 = 10 + 1 = 11

solution is (5, 11 )

This is a system. put the first equation under the second one and subtract. y - y = 0. 2x - 3x = -x. 1 - (-4) = 5. so the result is 0 = -x +5 or x = 5. plug x into either equation and y = 11. the answer is (5, 11).

we know that

applying the law of sines

°

so

∠j=18°

∠k=29°

∠l=180-(18+29)=133°

the answer part a) is

the measure of angle k is  ≈29°

part b)  the measure of angle k could also be

(180-29)=151°

so

∠j=18°

∠k=151°

∠l=180-(18+151)=11°

the answer part b) is

the measure of angle k could also be 151°

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hello i am doing good for you that it's summer in your country or state ; )

btw in my country we just have sun and rain as (because i live in the caribbean lol)

also, thx a lot for the points : )