You have a total of 52 dimes and quarters. You have 10 more quarters than dimes. Which system of equations can you use to find the number z of quarters and number y of dimes you have? Use the system to
determine how much money you have in quarters and dimes.

9514 1404 393

  z + y = 52; z - y = 10; z = 31; y = 21; $9.85 total

Step-by-step explanation:

The variables are defined in the problem statement. The equations could be ...

  z + y = 52 . . . . . . total number of coins

  z - y = 10 . . . . . . . 10 more quarters than dimes

These equations can be solved by adding them together.

  (z +y) +(z -y) = (52) + (10)

  2z = 62 . . . . . . . simplify

  z = 31 . . . . . . . . . divide by 2

  31 -10 = y = 21 . . . . find the number of dimes

There are 31 quarters and 21 dimes.

The value of the coins is ...

  31($0.25) +21($0.10) = $7.75 +2.10 = $9.85

rick has $1400 and sally has $1500

step-by-step explanation:

to find amount of money rick has after 10 years :

principal = $1000 , time = 10 years , rate = 4% annually

to find amount of money sally has after 10 years :

her friend gives to pay her $50 per year, therefore money she has after 10 years = 50 × 10 = $500

also, sally gets $1000 after 10 years,

therefore, total amount of money sally has after 10 years = 500 + 1000 = $1500

so, after 10 years : rick has $1400 and sally has $1500

the simplified form is

step-by-step explanation:

we want to simplify the expression,

let us change the middle bar to a normal division sign to obtain,

we multiply the first fraction by the reciprocal of the second fraction to obtain,

we factor to obtain,

we cancel the common factors to get,

we simplify to get,

the correct answer is b