Four horses are pulling a wagon. each horse drinks 45,000 milliliter of water each day. how many liters of water will the horses drink in 5 days

900 liters

Step-by-step explanation:

Given : Four horses are pulling a wagon.

Each horse drinks 45,000 milliliter of water each day.

We know that 1 liter = 1000 milliliters

Then, 1 milliliter= liter

⇒45,000 milliliters =   liters

i.e. Each horse drinks 45 liters of water each day.

Then, amount of water drunk by 4 horses each day =

⇒ Amount of horses will drink in 5 days =

Hence, the horse will drink 900 liters of water in 5 days.

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

the answer will be b x² +x-1

step-by-step explanation: