Please..I'm desperate. I have a D in this class.. Find an equation of the tangent line to the curve at the given point. y = 6x - x^3, (1,5)​

Step-by-step explanation:

Recall that the first derivative of an equation gives us the SLOPE for the tangent line.

So first, we should find the first derivative.

With the first derivative, we can solve for the SLOPE of the tangent line at (1,5).

Using x = 1.

A tangent line is a line. And has the form

Where m is the SLOPE of the line. and b is the y-intercept.

To get to this equation, let's use the point-slope technique.

Solve for slope, substitute it into this equation for m and solve. That is the equation of the tangent line at the point (1,5).

it's d

step-by-step explanation:

- (2, -7)

- lines r and s and lines t and u must be parallel