In △ABC, m∠B = 90°, m∠C = 15°, M ∈
BC. If m∠BAM = 60°, AM = 10 in. Find: AB
URGENT

Step-by-step explanation:

You end up with a 30°-60°-90° triangle inside of △ABC.

The sides of a 30°-60°-90° triangle are always in the ratio 1:√3:2.

AB is opposite the 30° angle. AM is opposite the 90° angle and has length 10, so AB is half the length of AM.

AB = 5 units.

since the airplane is moving with constant speed then the distance travelled can be calculated by x=u*t

in km/h would be:

x=640*3.5=2.240 km

in m/s would be:

u=640 km/h= 640.000 m/h =640.000/ 3600 m/s =177.8 m/s

t= 3.5 h= 3.5 * 3600 s=12.600 s

then x=u*t= 177.8*12.600= 2.240.280 m

0.02

step-by-step explanation:

time of 9 192 631 770 periods of the radiation corresponding to the transition between the 2 hyperfine levels of the ground state of the caesium 133 atom at 0 k (but other seconds are sometimes used in astronomy)