Given quadrilateral abcd, where ab || cd, _abc _ _cda, and a diagonal ac. which method can be used to prove triangleabc _ trianglecda?

f angle-angle-side (aas)
g side-side-angle (ssa)
h side-angle-side (sas)
j side-side-side (sss)

Option f Angle Angle Side (AAS)

Step-by-step explanation:

Given is a quadrilateral ABCD with two parallel sides AB and CD

AC the diagonal will also be a transveral and hence makes equal angles

(interior angles theorem)

Angle BAC = CAD

Also given that Angle ABC = angle CDA

AC =AC (reflexive property)

Hence by angle angle side axiom, the two triangles would be congruent

Option f( Angle Angle Side (AAS)

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet

(3x-8) or (3x+8)

step-by-step explanation: