A cyclist is riding a bicycle whose wheels have a diameter of 2.1 feet. Suppose the wheels turn at a rate of 260 revolutions per minute. (a) Find the angular speed of the wheels in radians per minute. (b) Find the speed of the cyclist in feet per minute. Do not round any intermediate computations, and round your answer to the nearest whole number.

a.1633rad/min

b.1715feet/min

Step-by-step explanation:

We are given that

Diameter of wheel, d=2.1 feet

Radius of wheel, r=feet

Rate=260 rev/min

a. We have to find the angular speed of the wheel in rad/min

1 rev=radian

Where

Using the value

Angular speed=

Angular speed,

(b)

Speed=

Using the formula

Speed of  the cyclist=feet/min

Speed of  the cyclist=1714.65feet/min

he sells x mount because thats eqivilqant to the maz and then divided into quarters

step-by-step explanation:

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl