3(r+2)+5(2-r) =-32 can someone tell em the answer to that please

r = 24

Step-by-step explanation:

3(r+2)+5(2−r)=−32

Step 1: Simplify both sides of the equation.

3(r+2)+5(2−r)=−32

(3)(r)+(3)(2)+(5)(2)+(5)(−r)=−32(Distribute)

3r+6+10+−5r=−32

(3r+−5r)+(6+10)=−32(Combine Like Terms)

−2r+16=−32

−2r+16=−32

Step 2: Subtract 16 from both sides.

−2r+16−16=−32−16

−2r=−48

Step 3: Divide both sides by -2.

−2r/-2 = -48/-2

r = 24  

r = 24

3(r+2)+5(2-r) =-32

this equals (if we do the multiplication)

3r+6+10-5r=-32

this equals  (if we simplify)

-2r+16=-32

this equals  (because we are subtracting from 1 side, we must subtract from the other)

-2r=-48

r=24

.632

step-by-step explanation:

6 * 1/10 = 3/5

3*0.01 = 0.03

3/5 + 0.03 = .63

2*0.002 = .002

.63 + 0.002 = .632

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step-by-step explanation: