Simplify 3 over quantity of 5 minus 6 i
quantity of 15 plus 18 i over 61
quantity of negative 15 plus 18 i over 61
3 i over quantity of 6 plus 5 i
quantity of 15 plus 18 i over negative 11

Quantity of 15 plus 18 i over 61

Step-by-step explanation:

Here, the given expression,

3 over quantity of 5 minus 6 i

To simplify this we need to multiply the numerator and the denominator by the complex conjugate of the denominator,

Since, denominator = 5-6i,

Its conjugate = 5 + 6i

Multiply and divide above fraction by 5 + 6i,

  ( (a+b)(a-b) = a² - b² )

  ( i² = -1 )

= quantity of 15 plus 18 i over 61

First option is correct.

19.

step-by-step explanation:

you add the 9 in the tens column since it is a single digit and 9 plus zero is 9 so it is 19

step-by-step explanation:

this is not a question