Kendra is flying a kite. the angle of elevation from kendra to the kite is 56á. if the distance from kendraís hands to the kite is 50 feet, what is the horizontal distance from kendra to the point directly under the kite (point b)? round your answer to the nearest tenth.

Assuming that the string of the kite does not sag. It then serves as the hypotenuse of the right triangle. The horizontal distance is the length of the base of the triangle. The horizontal distance can the be calculated using trigonometry: h = 50 cos(56 deg) = 28.0 ft.


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-2x + 7 = 7

subtract 7 from both sides.

-2x = 0

divide both sides by -2.

x = 0

the value of x is equal to 0.