A furniture factory makes a 4-piece desk. Quality control at the factory has randomly sampled numerous desk sets and determined the number of damaged pieces in each set.
The table below is a partially completed probability distribution for the random variable X, where X
represents the number of damaged pieces in a randomly selected desk set from this factory.
X
0
1
2
3
4.
P(X)
0.75
0.14
0.07
0.03
?
What is the probability that a randomly selected desk set contains exactly 4 damaged pieces?
P(X = 4) =
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x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

i think its a and d

step-by-step explanation:

22.83 repeating

step-by-step explanation:

137 ÷ 6 is 22.8333333 therefore we understand that 3 is repeating.

happy to

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