Acupboard contains 5 pairs of shoes, each of a different style. how many ways are there to select 4 of the shoes from the cupboard so that the selection contains exactly one matching pair? note that each pair of shoes consists of distinguishable left and right foot.

The solution to the problem is as follows:

If there are 6 pairs of shoes:

C(6,1) = choose the matching pair = 6 choices. 
C(10,1) = 1 shoe from the other 10. 
Now you cannot choose the mate of that one, 
so you have 8 other shoes to choose from. 

6 * 10 * 8 = 480 choices of "4 shoes". 
But then we must divide by 2, because the last two shoes 
could be chosen in either order. 

That gives 240 choices - same as your teacher's answer, 
but via a different route. 


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The answer is a 5/20 because if u add all of the marbles there are 20 and there are 5 red marbles so 5/20 is the answer mark as brainliest