If a number y has a positive integer factors then y and 2z integer factors. Is it true? how?

Given:

x is a factor of y --> , for some non-zero integer ;

y is a factor of z --> , for some non-zero integer ;

So, .

Question: is z even? Note that will be even if either or is even

(1) even --> either even, so the answer is directly YES or is even (or both). But if is even and as then z must be even too (one of the multiples of z is even, so z is even too). Sufficient.

(2) even --> as then as one of the multiples of z even --> z even. Sufficient.

D.

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x

answer: c, the green line

step-by-step explanation:

there is no black line, eliminate b.

simple interest implies periodic payments, but the red line shows no payments, eliminate d.

simple interest has equal payments. if paid say every day, the graph is about a straight line (actually a stairstep).

the yellow line is not straight, eliminate a.

check: the green line is straight, answer is c.

simple interest with positive interest rate gives a straight line sloping up to the right. green line:

g(t) = $100 + ($200-$100) ÷ (20 years) × (t years)

= $100 + (4%/year) × ($100)(t years)

incidentally, the yellow line curving upward represents continuously compounded interest

y = $100 × 2^(t years / (14 assuming the yellow line hits $200 at 14 years. 2^0 is 1, so y(0) = $100; 2^(14/14) is 2, so y(14) = $200.