Due very soon so if someone could answer soon-ish it would be very helpful and much appreciated <3<3<3 1) A straight line is perpendicular to y=2x+5 and passes through (0,3).
What is the equation of the line??
2) A straight line is perpendicular to y=0.5x+3 and passes through (3,5).
What is the equation of the line??
3) A straight line is perpendicular to y=4-5x and passes through (20,5).
What is the equation of the line??

See explanations below

Step-by-step explanation:

We are going to be using the point slope form of equation of a line for all the question, This is expressed as;

y-y0 = m(x-x0)

1) For a straight line is perpendicular to y=2x+5 and passes through (0,3).

Slope of the line m = 2

Slope of the line perpendicular M = -1/m

M = -1/2

Substituting M = -1/2 and the point (0,3) into the equation

y-y0 = m(x-x0)

y - 3 = -1/2(x-0)

y-3 = -x/2

2(y-3) = -x

2y-6 = -x

-x-2y = -6

x+2y = 6

The required equation is x+2y = 6

2) For a straight line is perpendicular to y=0.5x+3 and passes through (3,5).

Slope of the line m = 0.5

Slope of the line perpendicular M = -1/m

M = -1/0.5

M  = -2

Substituting M = -2 and the point (3,5) into the equation

y-y0 = m(x-x0)

y - 5 = -2(x-3)

y-5 = -2x+6

y+2x = 6 + 5

y+2x = 11

The required equation is y+2x = 11

3) A straight line is perpendicular to y=4-5x and passes through (20,5).

Slope of the line m = -5

Slope of the line perpendicular M = -1/m

M = -1/-5

M  = 1/5

Substituting M = -2 and the point (20,5) into the equation

y-y0 = m(x-x0)

y - 5 = 1/5(x-20)

5(y-5) = x-20

5y-25 = x-20

5y-x = -20+25

5y-x = 5

The required equation is 5y-x = 5

x -

median = 1.25

range = 12-14.5

interquartile = q12-q14.5

y -

median = 1

range = 15-17

interquartile = q15-q17