Using 3.14 for 11, what is the volume to the nearest tenth of a cone that has a helght of 17 meters and a base with a radius of 6 meters?

904.9m^3

Step-by-step explanation:

Given data

h= 17 m

r= 6 m

V= 4/3πr^3

substitute

V= 4/3*3.142*6^3

v=4*3.142*216/3

v=2714.688/3

v= 904.9m^3

Hence the volume is 904.9m^3

answer for #1 is c

answer for #2 is d

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a) 7x=7

step-by-step explanation: