Math help: Variables I need help solving these two questions, explanations would be greatly appreciated.

1. h = 11 cm

2. d = 220 km

Step-by-step explanation:

1. A = 1/2bh

Where,

A = 66 cm²

b = 12 cm

A = 1/2bh

66 = 1/2 * 12 * h

66 = 6h

h = 66/6

h = 11 cm

2. s = d/t

Where,

s = 110 km/h

t = 2h

s = d/t

110 = d/2

Cross multiply

110 * 2 = d

d = 220 km

hello from mrbilldoesmath!

answer:

x - 3

discussion:

x^2 - 9 = (x-3) (x+3)   so

(x^2-9)/ (x + 3) = x-3

you,

mrb

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v