\:\begin{pmatrix}1&2&3\\ \:1&1&1\\ \:0&2&1\end{pmatrix}\begin{ pmatrix}6\\ \:-2\\ \:5\end{pmatrix}\:-R1+R2→\:R2

-14 is the answer

hope this : ))

both equations and proportions are better.

answer: (-8,4) are the coordinates of a

step-by-step explanation:

let the side of square abcd is x .

thus the area of square abcd is .

now, by the diagram area of triangle ead= 1/2 × ea × ad = 1/2 × ea × x

( because ad is the side of square)

and, according to the question,

the areas of square abcd and right ead are equal.

⇒

⇒ea=2x

thus, ea: ab=2: 1

therefore, point a divides line segment eb into the ratio 2: 1.

⇒ by sectional formula coordinates of a are,

=

=

=(-8, 4)

thus the coordinates of a are (-8,4)