Lunches can be made consisting of exactly one entrée, one drink, and one snack. If all lunch options are equally likely, what is the probability of randomly choosing a lunch that does not contain the veggie wrap
has milk or water, and
has fruit as the snack.
Write your answer as a percentage, to the nearest percent.

Entrée Chicken Cutlet Veggies Wrap Lasagna
Drink Milk Water Iced Tea
Snack Fruit Chips Jello

%

4/27=14.8%

Step-by-step explanation:

In order to solve this, we have to see first each option possible, there are 2/3 of possibilities that a random Entrée ends up being Chicken Cutlet or Lasagna, then you have again 2/3 chances to get milk or water, and as you only want fruit the chances are 1/3 that you get that.

In order to calculate if this could happen at random we have to multiply all of the odds:

So we know that for every 27 times you pick a lunch at random, 4 times it will not have the Veggie Wrap, contain milk or water, and will have fruit as the snack.

step-by-step explanation:

|ab| = 1.4 = 4

h = 1.4 = 4

a(abc) area = 4.4 = 16/2 = 8

area of abc = 8 cm^2

good luck ! ; )

no ,sorry if you needed it but you can ask and try to see if any one will anwser ,

step-by-step explanation:

by good luck mark me as brainliest

have a nice day