Please please please help me please

Each term is a sum of the two previous terms like the fibonacci sequence, but the sum of the two starting terms of the lucas sequence is followed by 2 then 1, rather than 0 then 1 for the fibannaci sequence.

These are integer sequences.

The sum of the two previous terms can be represented by:

fn = fn-1 + fn-2.

These numbers can be obtained by adding the previous corresponding term of the fibonacci sequence by the next corresponding term to get the corresponding number of the lucas sequence.

Ln = { 2 if n = 0

1 if n = 1

Ln-1 + Ln-2 if n > 1

Fn+1 + Fn-1 = Ln

f(0) = -1

f(1) = 2, f(2) = 1, f(3) = 3, f(4) = 4, f(5) = 7, f(6) = 11

f(12) = 199

f(12) = f(11) + f(10) = (f(10) + f(9)) + (f(9) + f(8)) =

given f(n) = f(n-1) + f(n-2)

f(12) = f(1) + f(2) = f(2) + f(3) = f(3) + f(4) =

f(4) + f(5) = f(5) + f(6) = f(6) + f(7) =

f(7) + f(8) = f(8) + f(9) = f(9) + f(10) =

f(10) + f(11) = f(12) →

f(12) = 2 + 1 = 1 + [3] = 3 + [4] = 4 + [7] =

7 + [11] = 11 + [18] = 18 + [29] = 29 + [47] =

47 + [76] = 76 + [123] = 199

Explicit formula

for n is an integer.

Nth term of the lucas sequence.

As you can see, the golden ratio

( 1 + √5 / 2) appears in here.

L(n) = ((1 + √5) / 2)ⁿ⁻¹ + ((1 – √5) / 2)ⁿ⁻¹

1/3 + 1/5 = 8/15.

step-by-step explanation:

hope it

so what is the problem what are they asking you to solve

step-by-step explanation:

so what is the problem what are they asking you to solve