What is the equation of the line that passes through the point (6, 3) and has a slope of -2?

We know the equation of a line is y=mx+b. We know the slope (m) is -2 and all we need is the intercept (b).

Since we know one point, we can plug in 6 for x and 3 for y (along with -2 for m) in our equation and then solve for b.

3= -2*6 + b

3= -12 + b

15 = b

Since we now know the intercept we can now write our equation:

y= -2x + 15

circumference divided by 3.141592654 then timesthe radius twice

step-by-step explanation:

circumference divided by 3.141592654 then timesthe radius twice

for this pair of functions g(x)=x-2 and f(x)=|x| is (g o f)(a)= |a| -2

step-by-step explanation:

g(x)=x-2

f(x)=|x|

(g o f)(a)=?

(g o f)(x)=g(f(x))

(g o f)(x)=g(|x|)

(g o f)(x)=|x|-2

(g o f)(a)=|a|-2