A total of 110 gallons of water can follow through Hose B in minutes. Which hose has a faster water ow rate, in gallons per minute, and what is that rate?

Hose B

Step-by-step explanation:

Charles needs to fill a large fish tank with water using a hose. he has two hoses from which to choose. Water flows through each hose at a constant rate. The graph below shows the amount of water, in gallons , that flows through holes A based on the number of minutes used. A total of 110 gallons of water can flow through Hose B in 10 minutes. Which hose has a faster water rate, in gallons per minute, and what is that rate?

Solution:

The equation of a linear function is:

y = mx + b

where m is the rate of change and b is the initial value of y.

The equation of a line passing through two points is given by:

Let y represent the amount of water in gallons and let x represent the time in minutes.

For hose A, we can see that the graph passes through the point (0, 0) and (2, 12). Hence:

Therefore hose A has a flow rate of 6 gallons per minute.

110 gallons of water flow through hose B in 10 minutes. Therefore:

Flow rate of hose B = 110 gallons / 10 minutes = 11 gallons per minute

Therefore hose B has a higher flow rate

a 4/6 = 9/12   not proportional

step-by-step explanation:

to find which are not proportional, we can use cross products

if it is true, they are proportional.   if it is not true, they are not proportional.

a 4/6 = 9/12

4* 12 = 6*9

48 = 54

not this is not proportional  

b 2/3 = 12/18  

2* 18 = 3 * 12

36 = 36

this is proportional

c 5/4 = 10/8  

5*8 = 4*10

40 = 40

this is proportional

d 7/5 = 35/25

7*25 = 5 * 35

175 = 175

is proportional

so, converting firstly the mixed fractions to improper fractions and then "adding".