In a drill, Mark gives Fred a 45 meter head start. After t seconds, Fred is a distance 5t +45 from the starting line andMark is a distance of 6t from the starting line. How far ahead of Mark is Fred after t seconds?

After t seconds, Fred is far away from Mark by (45-t).

Step-by-step explanation:

Given: Mark gives Fred a 45meter head start.

After t seconds, the distance of  Fred from the starting point = 5t+45

The distance of Mark from the starting point = 6t

Now, Distance between Fred and Mark after t seconds = Location of Fred - Location of Mark

= (5t+45)-6t

= 5t+45-6t

= 45-t

Hence, After t seconds, Fred is far away from Mark by (45-t).

75

step-by-step explanation:

you do x-29=46 (the number of cantaloupes sold)

in order to find x, you have to find what minus 29 equals 46, meaning you'd have to add 29 to 46.

29+46=75

if you replace x with 75, the equation looks like:

75-29=46

x=75