In Mr. Green's homeroom, 6 students have no siblings, 7 students have 1 sibling, 10 students have 2 siblings, and 3 students have 3 or more siblings. Is it likely that a student chosen at random will have only 2 siblings?

No, it is unlikely that a student chosen at random will have only 2 siblings.

Step-by-step explanation:

Given: Number of students with 2 siblings = 10

Total students = 6+7+10+3 =26

The probability of choosing a student with only 2 siblings =

Hence, it is not likely that a student chosen at random will have only 2 siblings.

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.