At a wedding reception, the caterer served fishing chicken. The fish dinner cost $12 per person in the chicken cost $9 per person. The caterer charged 2544 total for the dinner. If 232 people went to the reception, how many people had fish how many had chicken.

80 persons haf fish and 152 persons had chicken

Step-by-step explanation:

Given data

let the number of persons that had fish be x and chicken be y

so

12x+9y=25441

x+y= 2322

from 2

x= 232-y

substitute the value of x in 1

12(232-y)+9y=2544

2784-12y+9y=2544

2784-3y=2544

3y= 2784-2544

3y=240

y= 240/3

y=80

put y= 80 in 2

x+80= 232

x= 232-80

x=152

Hence 80 persons haf fish and 152 persons had chicken

the answer is y < -3 or   y > 3

-3y > 7 + 2

-3 y > 9

y < -3

the answer is 21%.