In the accompanying diagram ab is tangent to circle O at B and ACD is a secant. If AB=9 and AD=27, find AC

AC = 3

Step-by-step explanation:

Based on tangent and secant theorem, thus:

AB² = AC × (AC + CD)

AB = 9

AD = AC + CD = 27

Plug in the values

9² = AC × (27)

81 = AC × 27

Divide both sides by 27

81/27 = AC

3 = AC

AC = 3

b. 13

step-by-step explanation:

as there are 13 students in bowling class therefore the most reasonable answer is b as only 13 students are in the bowling class.