Assume that x = x(t) and y = y(t). Let y = x^2 + 6 and
dx/dt=4 when x=1
Find dy/dt when x = 1

= 8

Step-by-step explanation:

Given:

x = x(t) and y = y(t)

Let y = x² + 6

By differentiating the given equation with respect to t,

Since, when x = 1

[By substituting the values of and x = 1]

= 8

< 6 cm to > 26 cm i believe

step-by-step explanation:

x = 25

step-by-step explanation:

a^2+b^2=c^2

7^2+24^2=c^2

49+576=625

sqrt625=25

x=25