Forty percent of the 70 buttons in the box had 5 holes a. What fraction of the buttons did not have 5 holes?

b. How many buttons did not have 5 holes?

a. 0.6

b. 42 buttons

Step-by-step explanation:

a. What fraction of the buttons did not have 5 holes?

Since forty percent of the 70 buttons in the box had 5 holes, the number of buttons in the box that doesn't have 5 holes will be:

= 100% - 40%

= 60%

= 60/100

= 0.6

b. How many buttons did not have 5 holes?

This will be:

= 60% × 70

= 0.6 × 70

= 42 buttons

english, cause i can’t you

ok so the answer to your question is simple as long as you look at the different dimensions that contain the exemplary letters that combined in the right order give you words that eventually within the 5th dimension will conform and give you the correct answer to your question. hope i , stop looking at this easily, look at it with a spectral view.

step-by-step explanation:

told you