Rita is designing a building shaped like a pyramid that's cut off in a plane parallel to its base (this is called a truncated pyramid).The building has a 64 × 64 m square base and is 36 m tall. The cut off section has a 16 × 16 m, square base and is 12 m tall. What is the volume of the buliding?

48128m^3

Step-by-step explanation:

Given data

For the building

L=64m

W= 6m

H= 36m

The volume is

V= LWH/3

V=64*64*36/3

V=147456/3

V=49152m^3

For the off-Cut

L=16m

W= 16m

H= 12m

The volume is

V= LWH/3

V=16*16*12/3

V=3072/3

V=1024m^3

Hence the volume of the truncated part/Building

= Volume of building-volume of off-cut

=49152-1024

=48128m^3

t= half of the arc subtended by t.

r= half of the arc subtended by r.  

t+r= half of the arc subtended by t + half of the arc subtended by r= half of 360=180

step-by-step explanation: