A function is given: f(x) = 3x + 12

a. Determine the inverse of this function and name it g(x).

b. Use composite functions to show that these functions are inverses.

c. Evaluate f(g(–2)). Explain: What is the domain?

See explanations below

Step-by-step explanation:

Given the function

f(x) = 3x+12

Let y = f(x)

y = 3x+12

Replace y with x

x = 3y+12

Make y the subject

3y = x-12

y = (x-12)/3

Hence the required inverse is!

g(x) = (x-12)/3

b) To show that the functions are inverses, we must show that f(g(x)) = g(f(x))

f(g(x)) = f((x-12)/3)

Replace x in f(x) with x-12/3

f(g(x)) = 3(x-12)/3 +12

f(g(x)) = x-12+12

f(g(x)) = x

Similarly for g(f(x))

g(f(x)) = g(3x+12)

g(f(x)) = (3x+12-12)/3

g(f(x)) = 3x/3

g(f(x)) = x

Since f(g(x)) = g(f(x)) = x, hence they are inverses of each other

c) Given f(g(x)) = x

f(g(–2)) = -2

The domain is the input variable of the function. Hence the domain is -2

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

~

c: y > - 1/6x + 1

step-by-step explanation:

dashed line - meaning this < or > also not equal

solid line - meaning this < or > also equal

your answer is c because y > means up & it's shaded up, but y < means down

hope this ! : )