THIS question uses Bayes Rule and I have ABSOLUTELY NO IDEA HOW TO SOLVE IT so if you could provide a step by step that'd be great On the TV show Iron Chef, the weekly challenger must choose one of the three Iron Chefs (Michiba, Sakai, and Chen) to battle. Based on the data on Wikipedia's Iron Chef page, suppose that if the challenger selects Michiba, there is only a 13% probability they will be able to defeat him. For Sakai and Chen, suppose this probability is 18% and 25% respectively. Since the challenger specializes in Japanese cuisine, you believe there is a 50% probability they will challenge Michiba, a 25% probability they will challenge Sakai, and a 25% probability they will challenge Chen.

Here is part 1

What is the probability the challenger selected Sakai, given that the challenger is known to have won?

Part 2

What is the probability the challenger selected Chen, given that the challenger is known to have won?

that is the sum

step-by-step explanation:

there are no other answers without knowing the variables values

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!

-8/2y-8=5/y+4-7y+8/y^2-16

we move all terms to the left:

-8/2y-8-(5/y+4-7y+8/y^2-16)=0

we can not solve this equation