![\huge\boxed{\text{A) -3}}](/tpl/images/1103/2465/97d8c.png)
Step-by-step explanation:
To find the value of this equation when
, we can substitute this value inside the equation and use PEMDAS to successfully find the value.
With the expression of
, let's substitute -2 in as x.
![2(-2)^2 + 4(-2) - 3](/tpl/images/1103/2465/be067.png)
Now let's follow PEMDAS to solve this equation.
PEMDAS states that when solving an expression/equation, the order we must follow is
ParenthesesExponentsMultiplication/DivisionAddition/Subtraction
We can now solve for this.
We see that exponents come before multiply and dividing. Therefore:
![2(-2)^2 = 2 \cdot (-2)^2 = 2 \cdot 4 = 8](/tpl/images/1103/2465/226b5.png)
So the value of our first term is 8.
Our second term will be
, and our last term will remain -3.
Adding these values together:
![8 - 8 - 3 = -3](/tpl/images/1103/2465/7c986.png)
Therefore, the value of this expression when x = -2 is -3.
Hope this helped!