The simplest polynomial function with zeros 7, square root 13 and 27i would be of what degree

The simplest polynomial function is .

Step-by-step explanation:

A n-th order polynomial in factorized form is defined by:

(1)

Where:

- Independent variable.

- Dependent variable.

, ,..., , - Roots of the polynomial.

We know that three roots, two real and a complex root. By Quadratic Formula,  a second order polynomial has two conjugated complex number of the form and . Hence, there is an additional zero: .

By applying (1), we have the following polynomial when all roots are used:

By factorization and algebraic handling we have the simplest polynomial function:

The simplest polynomial function is .

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°

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step-by-step explanation: