(x + 1)^7
Use Pascal's Triangle and Binomial. Theorem

x⁷+7x⁶+21x⁵+35x⁴+35x³+21x²+7x+1

Step-by-step explanation:

(x + 1)⁷: Pascal's Triangle for (a+b)⁷

a₇+7a⁶b+21a⁵b²+35a⁴b³+... + 7a¹b⁶ + b⁷

x⁷+7x⁶+21x⁵+35x⁴+35x³+21x²+7x+1

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.

the answer is:

the answer is:

to solve the problem, we need to remember the quotient of power property, it's defined by the following relation:

if we have a quotienf of powers that have the same base, we need to keep the same base and subtract the exponent of the denominator power to the exponent of the numerator power.

so, we are given the expression:

then, calculating we have:

hence, the answer is:

have a nice day!