The price of a shirt has been discounted by $20. The sale price is $24.95. What percent of the original list price is the discount? (a) Use the verbal description to write a verbal model.
o change in price = (original price)/(percent)
o change in price = (percent)(original price)
O change in price = (percent) - (original price)
o change in price = (original price) + (percent)
O change in price = (percent)/(original price)
(b) Assign labels to the quantities in the verbal model.
--Select-
= 20
---Select-
---Select-
= 44.95
(C) Use the labels to write a mathematical model.
(d) Solve the problem. (Round your answer to the nearest whole number.)
%

this is an example

Step-by-step explanation:

There are a few different ways to approach this problem, including the following two methods.

1) Find 20% of the original price, then subtract that amount from the original price. 

    To find a percentage of a number, you multiply the number by the percentage.  (You are finding a part of a whole.)

                   20% = 20/100 = 1/5    or   20% = 0.20

    Original Price: $24   Find 20% of $24.                         (Note: "of" is taking part of a whole, so you multiply.)

                    0.20 x 24 = 4.80            This is the mark down, or the amount you subtract from original price.

    Sale Price = Original Price - Mark Down   

                   =   24.00 - 4.80

                   =   19.20

2) If you save 20%, you are still paying 80%. (100-20 = 80) Therefore the sale price is 80% of the original price.

                    80% = 80/100 = 4/5     or    80% = 0.80

     Sale Price = 80% of Original Price

                    = 0.80 x 24

                    = 19.20

360 different combinations

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.