Mr. Hayes has 11 straw bundles to use forr bedding in his horse stalls. What is the greatest number of stalls he can fill if each stall holds exactly 4 bundles

2 stalls

Step-by-step explanation:

Mr. Hayes has 11 straw bundles to use forr bedding in his horse stalls. What is the greatest number of stalls he can fill if each stall holds exactly 4 bundles

1 stall = 4 bundles

4 bundles = 1 stall

11 bundles = x

Cross Multiply

4x = 11

x = 11/4

x = 2 3/4 stalls

The greatest number of stalls he can build is 2 stalls

hello from mrbilldoesmath!

answer:

(7 x + 6 y) (49 x^2 - 42 x y + 36 y^2)

discussion:

the trick is to recognize that 343 = 7^3 and 216 = 6^3 and, in general,

a^3 + b^3 =   (a + b) (a^2 - a b + b^2).

in our case

343x^3+216y^3   =   (7x)^3 + (6y)^3

so take a = 7x and b = 6y in the above equation to get the answer.

you,

mrb