pls this is a simultaneous equation- one linear one quadratic a-2b =2 (1). a²+b²+2a -3b =19 (2). pls I need it urgently thanks

Hence a = 3.66 and -3.628

b = 0.834 and -2.634

Step-by-step explanation:

Given the equations

a-2b =2 (1)

a²+b²+2a -3b =19 (2).

From 1;

a = 2 + 2b

Substitute into 2

(2+2b)²+b²+2a -3b =19

Expand

4 + 8b + 4b²+b²+2(2+2b)-3b = 19

4b²+b²+8b+4b+4+4-3b = 19

5b²+9b+8 = 19

5b²+9b-11 = 0

b = -9±√81+4(55)/2(5)

b= -9±√301/10

b = -9+17.34/10 and -9-17.34/10

b = 8.34/10 and -26.34/10

b = 0.834 and -2.634

Since a = 2+2b

a = 2+2(0.834)

a= 2 +1.668

a = 3.668

Also

a = 2+2(-2.634)

a = 2 - 5.628

a = -3.628

Hence a = 3.66 and -3.628

b = 0.834 and -2.634

x=17

step-by-step explanation:

solve 3x-24=x+10

then that makes it 2x=34 because you subtract an x from both sides to get rid of the one on the right, and then you add 24 to both sides to get rid of the 24 on the left

divide by both sides by 2 to get your answer so that you can get your answer