How many numbers between 4000 and 5000 can be formed with the digits 2, 3, 4, 5, 6, 7? How many of these numbers are divisible by 5?

36 numbers

Step-by-step explanation:

Number of digits in a number between 4000 and 5000 = 4

_ _ _ _

First digit of the number will be filled by 4.

So, the number of ways to fill the first digit = 1

4 _ _ _

If the given number is divisible by 5 then the last digit should be 5.

4 _ _ 5

So, the number of ways that the last digit should be 5 is = 1

Remaining 2 digits between 4 and 5 can be filled by any number given.

Therefore, number of ways that second place can be filled = 6

Similarly, number of ways that the third place of the number can be filled = 6

Now total number of ways = 1 × 6 × 6 × 1

                                             = 36

Therefore, numbers between 4000 and 5000, divisible by 5 = 36

the answer is 48m^2!

step-by-step explanation:

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204