Solve the system of equations 6x+3y=12 and 5x+y=7

x = 1; y = 2

Step-by-step explanation:

To find x:

Multiply (5x+y=7) by 3 to get the y's in both equation the same, and you will get 15x+3y=21.

Now the y's cancel out. Subtract the remaining equations: (15x=21) - (6x=12) and you get 9x = 9. Divide everything by 9 and you get x=1.

To find y:

You can substitute 1 for x in either equation. I will use (5x+y=7).

Substitute the 1 for x: 5(1)+y=7

Simplify: 5+y=7

Put like terms on the same side by subtracting 5 from both sides: y=2

Check:

6(1) + 3(2) = 12

6 + 6 = 12

12 = 12 - this is right

5(1) + (2) = 7

5 + 2 = 7

7 = 7 - this is right

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1 is c

2 is a

3 is a

step-by-step explanation: